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=(3/2)Y^2+6Y+1
We move all terms to the left:
-((3/2)Y^2+6Y+1)=0
Domain of the equation: 2)Y^2+6Y+1)!=0We add all the numbers together, and all the variables
Y!=0/1
Y!=0
Y∈R
-((+3/2)Y^2+6Y+1)=0
We multiply all the terms by the denominator
-((+3=0
We add all the numbers together, and all the variables
=0
Y=0/1
Y=0
Równanie nie ma rozwiązania
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